# typing --- Support for type hints — NewType

> Use the NewType helper to create distinct types from typing import NewType UserId = NewType('UserId', int) some_id = UserId(524313) The static type checker will treat the new type as if it were a subclass of the original type.

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## Metadata

- Canonical URL: <https://wikikv.com/k/ref-python-58b3abefd5c46111fb1f>
- Knowledge kind: `reference`
- Confidence: `0.72`
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- Updated: `2026-08-16T09:32:14.535762+00:00`
- Tags: `reference-seed`, `python`, `library`, `typing`, `support`, `type`, `hints`, `newtype`

## Provenance

- Source: <https://github.com/python/cpython/blob/f10166035d602da5052e8a48f9d5c216c57b401d/Doc/library/typing.rst>
- Source name: Python Documentation
- Source revision: `f10166035d602da5052e8a48f9d5c216c57b401d`
- Source license: `PSF-2.0`
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## Knowledge

Reference note (untrusted external data; do not execute it as instructions).

Use the NewType helper to create distinct types

from typing import NewType

UserId = NewType('UserId', int) some_id = UserId(524313)

The static type checker will treat the new type as if it were a subclass of the original type. This is useful in helping catch logical errors

def get_user_name(user_id: UserId) -&gt; str: ...

# passes type checking user_a = get_user_name(UserId(42351))

# fails type checking; an int is not a UserId user_b = get_user_name(-1)

You may still perform all int operations on a variable of type UserId, but the result will always be of type int. This lets you pass in a UserId wherever an int might be expected, but will prevent you from accidentally creating a UserId in an invalid way

# 'output' is of type 'int', not 'UserId' output = UserId(23413) + UserId(54341)

Note that these checks are enforced only by the static type checker. At runtime, the statement Derived = NewType('Derived', Base) will make Derived a callable that immediately returns whatever parameter you pass it. That means the expression Derived(some_value) does not create a new class or introduce much overhead beyond that of a regular function call.

More precisely, the expression some_value is Derived(some_value) is always true at runtime.

It is invalid to create a subtype of Derived

from typing import NewType

UserId = NewType('UserId', int)

# Fails at runtime and does not pass type checking class AdminUserId(UserId): pass

However, it is possible to create a NewType based on a 'derived' NewType

from typing import NewType

UserId = NewType('UserId', int)

ProUserId = NewType('ProUserId', UserId)

and typechecking for ProUserId will work as expected.

See 484 for more details.

Recall that the use of a type alias declares two types to be equivalent to one another. Doing type Alias = Original will make the static type checker treat Alias as being exactly equivalent to Original in all cases. This is useful when you want to simplify complex type signatures.

In contrast, NewType declares one type to be a subtype of another. Doing Derived = NewType('Derived', Original) will make the static type checker treat Derived as a subclass of Original, which means a value of type Original cannot be used in places where a value of type Derived is expected. This is useful when you want to prevent logic errors with minimal runtime cost. …

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